Base | Representation |
---|---|
bin | 10101111000010110001110… |
… | …100000010110101110101011 |
3 | 110121201121101010100112101211 |
4 | 111320112032200112232223 |
5 | 100103122330034111014 |
6 | 540355550001253551 |
7 | 26161320121161154 |
oct | 2570261640265653 |
9 | 417647333315354 |
10 | 96231133113259 |
11 | 287314379a1581 |
12 | a9622a39342b7 |
13 | 41907317074b1 |
14 | 19a987c6ba92b |
15 | b1d2d50d9cc4 |
hex | 57858e816bab |
96231133113259 has 2 divisors, whose sum is σ = 96231133113260. Its totient is φ = 96231133113258.
The previous prime is 96231133113257. The next prime is 96231133113277. The reversal of 96231133113259 is 95231133113269.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 96231133113259 - 21 = 96231133113257 is a prime.
Together with 96231133113257, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (96231133113257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48115566556629 + 48115566556630.
It is an arithmetic number, because the mean of its divisors is an integer number (48115566556630).
Almost surely, 296231133113259 is an apocalyptic number.
96231133113259 is a deficient number, since it is larger than the sum of its proper divisors (1).
96231133113259 is an equidigital number, since it uses as much as digits as its factorization.
96231133113259 is an evil number, because the sum of its binary digits is even.
The product of its digits is 787320, while the sum is 49.
The spelling of 96231133113259 in words is "ninety-six trillion, two hundred thirty-one billion, one hundred thirty-three million, one hundred thirteen thousand, two hundred fifty-nine".
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