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964731953 is a prime number
BaseRepresentation
bin111001100000001…
…010010000110001
32111020022110110002
4321200022100301
53433432410303
6235421315345
732623041413
oct7140122061
92436273402
10964731953
11455625439
1222b105b55
13124b3c413
14921aa9b3
1559a66788
hex3980a431

964731953 has 2 divisors, whose sum is σ = 964731954. Its totient is φ = 964731952.

The previous prime is 964731949. The next prime is 964731959. The reversal of 964731953 is 359137469.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 518381824 + 446350129 = 22768^2 + 21127^2 .

It is an emirp because it is prime and its reverse (359137469) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 964731953 - 22 = 964731949 is a prime.

It is a super-2 number, since 2×9647319532 = 1861415482278388418, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 964731898 and 964731907.

It is not a weakly prime, because it can be changed into another prime (964731959) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 482365976 + 482365977.

It is an arithmetic number, because the mean of its divisors is an integer number (482365977).

Almost surely, 2964731953 is an apocalyptic number.

It is an amenable number.

964731953 is a deficient number, since it is larger than the sum of its proper divisors (1).

964731953 is an equidigital number, since it uses as much as digits as its factorization.

964731953 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 612360, while the sum is 47.

The square root of 964731953 is about 31060.1344652595. The cubic root of 964731953 is about 988.1030071893.

The spelling of 964731953 in words is "nine hundred sixty-four million, seven hundred thirty-one thousand, nine hundred fifty-three".