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96602055701117 is a prime number
BaseRepresentation
bin10101111101101111101011…
…001101101111001001111101
3110200001001210100122022122012
4111331233223031233021331
5100130212002224413432
6541242212143501005
726230160665146641
oct2575575315571175
9420031710568565
1096602055701117
112886477a03a84a
12aa02160bb7765
1341b96c4b55405
1419bd7c8b90c21
15b27c93d98cb2
hex57dbeb36f27d

96602055701117 has 2 divisors, whose sum is σ = 96602055701118. Its totient is φ = 96602055701116.

The previous prime is 96602055701113. The next prime is 96602055701171. The reversal of 96602055701117 is 71110755020669.

Together with next prime (96602055701171) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 96036452432761 + 565603268356 = 9799819^2 + 752066^2 .

It is a cyclic number.

It is not a de Polignac number, because 96602055701117 - 22 = 96602055701113 is a prime.

It is a super-2 number, since 2×966020557011172 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (96602055701113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48301027850558 + 48301027850559.

It is an arithmetic number, because the mean of its divisors is an integer number (48301027850559).

Almost surely, 296602055701117 is an apocalyptic number.

It is an amenable number.

96602055701117 is a deficient number, since it is larger than the sum of its proper divisors (1).

96602055701117 is an equidigital number, since it uses as much as digits as its factorization.

96602055701117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 793800, while the sum is 50.

The spelling of 96602055701117 in words is "ninety-six trillion, six hundred two billion, fifty-five million, seven hundred one thousand, one hundred seventeen".