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97054243301 is a prime number
BaseRepresentation
bin101101001100011100…
…0100011100111100101
3100021111212200101201202
41122120320203213211
53042231341241201
6112330333132245
710004044312361
oct1323070434745
9307455611652
1097054243301
1138184654534
121698732a085
1391c943ab42
1449a9b382a1
1527d080cc6b
hex1698e239e5

97054243301 has 2 divisors, whose sum is σ = 97054243302. Its totient is φ = 97054243300.

The previous prime is 97054243289. The next prime is 97054243331. The reversal of 97054243301 is 10334245079.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 68400556225 + 28653687076 = 261535^2 + 169274^2 .

It is an emirp because it is prime and its reverse (10334245079) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 97054243301 - 210 = 97054242277 is a prime.

It is a super-2 number, since 2×970542433012 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (97054243331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48527121650 + 48527121651.

It is an arithmetic number, because the mean of its divisors is an integer number (48527121651).

Almost surely, 297054243301 is an apocalyptic number.

It is an amenable number.

97054243301 is a deficient number, since it is larger than the sum of its proper divisors (1).

97054243301 is an equidigital number, since it uses as much as digits as its factorization.

97054243301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90720, while the sum is 38.

The spelling of 97054243301 in words is "ninety-seven billion, fifty-four million, two hundred forty-three thousand, three hundred one".