Base | Representation |
---|---|
bin | 101101010111110111… |
… | …0100101101000000101 |
3 | 100022111120212011101111 |
4 | 1122233232211220011 |
5 | 3044023000143203 |
6 | 112432343525021 |
7 | 10016410064446 |
oct | 1325756455005 |
9 | 308446764344 |
10 | 97437506053 |
11 | 38360a28508 |
12 | 16a73759771 |
13 | 925a96c134 |
14 | 4a049c32cd |
15 | 28042b726d |
hex | 16afba5a05 |
97437506053 has 2 divisors, whose sum is σ = 97437506054. Its totient is φ = 97437506052.
The previous prime is 97437506021. The next prime is 97437506057. The reversal of 97437506053 is 35060573479.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 65675850529 + 31761655524 = 256273^2 + 178218^2 .
It is a cyclic number.
It is not a de Polignac number, because 97437506053 - 25 = 97437506021 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 97437505988 and 97437506006.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (97437506057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48718753026 + 48718753027.
It is an arithmetic number, because the mean of its divisors is an integer number (48718753027).
Almost surely, 297437506053 is an apocalyptic number.
It is an amenable number.
97437506053 is a deficient number, since it is larger than the sum of its proper divisors (1).
97437506053 is an equidigital number, since it uses as much as digits as its factorization.
97437506053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2381400, while the sum is 49.
The spelling of 97437506053 in words is "ninety-seven billion, four hundred thirty-seven million, five hundred six thousand, fifty-three".
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