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97913456801 is a prime number
BaseRepresentation
bin101101100110000011…
…0001100100010100001
3100100201202102222001222
41123030012030202201
53101011321104201
6112551505104425
710034246436116
oct1331406144241
9310652388058
1097913456801
1138585659336
1216b87028115
1393054539b4
144a4bcb890d
152830e7e91b
hex16cc18c8a1

97913456801 has 2 divisors, whose sum is σ = 97913456802. Its totient is φ = 97913456800.

The previous prime is 97913456783. The next prime is 97913456803. The reversal of 97913456801 is 10865431979.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 82587264400 + 15326192401 = 287380^2 + 123799^2 .

It is a cyclic number.

It is not a de Polignac number, because 97913456801 - 26 = 97913456737 is a prime.

Together with 97913456803, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (97913456803) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48956728400 + 48956728401.

It is an arithmetic number, because the mean of its divisors is an integer number (48956728401).

Almost surely, 297913456801 is an apocalyptic number.

It is an amenable number.

97913456801 is a deficient number, since it is larger than the sum of its proper divisors (1).

97913456801 is an equidigital number, since it uses as much as digits as its factorization.

97913456801 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1632960, while the sum is 53.

The spelling of 97913456801 in words is "ninety-seven billion, nine hundred thirteen million, four hundred fifty-six thousand, eight hundred one".