Base | Representation |
---|---|
bin | 10110010001111100000011… |
… | …010111000111110100000011 |
3 | 110211221201122010112102010021 |
4 | 112101330003113013310003 |
5 | 100320430434211014303 |
6 | 544223510220314311 |
7 | 26432344662541645 |
oct | 2621740327076403 |
9 | 424851563472107 |
10 | 97989735251203 |
11 | 2924a238a64724 |
12 | aba70980a2997 |
13 | 428a5140b9823 |
14 | 1a2aa2ada4895 |
15 | b4de10589ebd |
hex | 591f035c7d03 |
97989735251203 has 2 divisors, whose sum is σ = 97989735251204. Its totient is φ = 97989735251202.
The previous prime is 97989735251173. The next prime is 97989735251231. The reversal of 97989735251203 is 30215253798979.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 97989735251203 - 213 = 97989735243011 is a prime.
It is not a weakly prime, because it can be changed into another prime (97989735251263) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48994867625601 + 48994867625602.
It is an arithmetic number, because the mean of its divisors is an integer number (48994867625602).
Almost surely, 297989735251203 is an apocalyptic number.
97989735251203 is a deficient number, since it is larger than the sum of its proper divisors (1).
97989735251203 is an equidigital number, since it uses as much as digits as its factorization.
97989735251203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 257191200, while the sum is 70.
The spelling of 97989735251203 in words is "ninety-seven trillion, nine hundred eighty-nine billion, seven hundred thirty-five million, two hundred fifty-one thousand, two hundred three".
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