Base | Representation |
---|---|
bin | 11100100111001101000… |
… | …01001011010010101101 |
3 | 10110222121022201120212021 |
4 | 32103212201023102231 |
5 | 112101412210001143 |
6 | 2031350013310141 |
7 | 131012426056363 |
oct | 16234641132255 |
9 | 3428538646767 |
10 | 983120000173 |
11 | 349a36679213 |
12 | 13a650a95351 |
13 | 719280cc46c |
14 | 35824683633 |
15 | 1a88e894ced |
hex | e4e684b4ad |
983120000173 has 2 divisors, whose sum is σ = 983120000174. Its totient is φ = 983120000172.
The previous prime is 983120000143. The next prime is 983120000179. The reversal of 983120000173 is 371000021389.
983120000173 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 838885632649 + 144234367524 = 915907^2 + 379782^2 .
It is a cyclic number.
It is not a de Polignac number, because 983120000173 - 25 = 983120000141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (983120000179) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 491560000086 + 491560000087.
It is an arithmetic number, because the mean of its divisors is an integer number (491560000087).
Almost surely, 2983120000173 is an apocalyptic number.
It is an amenable number.
983120000173 is a deficient number, since it is larger than the sum of its proper divisors (1).
983120000173 is an equidigital number, since it uses as much as digits as its factorization.
983120000173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9072, while the sum is 34.
The spelling of 983120000173 in words is "nine hundred eighty-three billion, one hundred twenty million, one hundred seventy-three", and thus it is an aban number.
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