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983134343 is a prime number
BaseRepresentation
bin111010100110010…
…111000010000111
32112111221101210002
4322212113002013
54003140244333
6241315551515
733235334612
oct7246270207
92474841702
10983134343
11464a54424
122352bb59b
131288b35c9
14947db179
155b49e0e8
hex3a997087

983134343 has 2 divisors, whose sum is σ = 983134344. Its totient is φ = 983134342.

The previous prime is 983134277. The next prime is 983134357. The reversal of 983134343 is 343431389.

983134343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 983134343 - 214 = 983117959 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 983134297 and 983134306.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (983134393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 491567171 + 491567172.

It is an arithmetic number, because the mean of its divisors is an integer number (491567172).

Almost surely, 2983134343 is an apocalyptic number.

983134343 is a deficient number, since it is larger than the sum of its proper divisors (1).

983134343 is an equidigital number, since it uses as much as digits as its factorization.

983134343 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 93312, while the sum is 38.

The square root of 983134343 is about 31354.9731781100. The cubic root of 983134343 is about 994.3462092250.

The spelling of 983134343 in words is "nine hundred eighty-three million, one hundred thirty-four thousand, three hundred forty-three".