Base | Representation |
---|---|
bin | 1110000000001001111000000… |
… | …1110011100110100100001001 |
3 | 11210012202211101012112220011211 |
4 | 3200002132001303212210021 |
5 | 2013122140120100000014 |
6 | 13411343152345253121 |
7 | 414354615662311306 |
oct | 34002360163464411 |
9 | 4705684335486154 |
10 | 985332100000009 |
11 | 265a58aa6993493 |
12 | 92617b667941a1 |
13 | 333a5559119748 |
14 | 135464844380ad |
15 | 78dab384d6cc4 |
hex | 3802781ce6909 |
985332100000009 has 2 divisors, whose sum is σ = 985332100000010. Its totient is φ = 985332100000008.
The previous prime is 985332099999943. The next prime is 985332100000049. The reversal of 985332100000009 is 900000001233589.
It is an a-pointer prime, because the next prime (985332100000049) can be obtained adding 985332100000009 to its sum of digits (40).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 985332100000000 + 9 = 31390000^2 + 3^2 .
It is a cyclic number.
It is not a de Polignac number, because 985332100000009 - 29 = 985332099999497 is a prime.
It is not a weakly prime, because it can be changed into another prime (985332100000049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 492666050000004 + 492666050000005.
It is an arithmetic number, because the mean of its divisors is an integer number (492666050000005).
Almost surely, 2985332100000009 is an apocalyptic number.
It is an amenable number.
985332100000009 is a deficient number, since it is larger than the sum of its proper divisors (1).
985332100000009 is an equidigital number, since it uses as much as digits as its factorization.
985332100000009 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 58320, while the sum is 40.
The spelling of 985332100000009 in words is "nine hundred eighty-five trillion, three hundred thirty-two billion, one hundred million, nine", and thus it is an aban number.
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