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985332100000009 is a prime number
BaseRepresentation
bin1110000000001001111000000…
…1110011100110100100001001
311210012202211101012112220011211
43200002132001303212210021
52013122140120100000014
613411343152345253121
7414354615662311306
oct34002360163464411
94705684335486154
10985332100000009
11265a58aa6993493
1292617b667941a1
13333a5559119748
14135464844380ad
1578dab384d6cc4
hex3802781ce6909

985332100000009 has 2 divisors, whose sum is σ = 985332100000010. Its totient is φ = 985332100000008.

The previous prime is 985332099999943. The next prime is 985332100000049. The reversal of 985332100000009 is 900000001233589.

It is an a-pointer prime, because the next prime (985332100000049) can be obtained adding 985332100000009 to its sum of digits (40).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 985332100000000 + 9 = 31390000^2 + 3^2 .

It is a cyclic number.

It is not a de Polignac number, because 985332100000009 - 29 = 985332099999497 is a prime.

It is not a weakly prime, because it can be changed into another prime (985332100000049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 492666050000004 + 492666050000005.

It is an arithmetic number, because the mean of its divisors is an integer number (492666050000005).

Almost surely, 2985332100000009 is an apocalyptic number.

It is an amenable number.

985332100000009 is a deficient number, since it is larger than the sum of its proper divisors (1).

985332100000009 is an equidigital number, since it uses as much as digits as its factorization.

985332100000009 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 58320, while the sum is 40.

The spelling of 985332100000009 in words is "nine hundred eighty-five trillion, three hundred thirty-two billion, one hundred million, nine", and thus it is an aban number.