Base | Representation |
---|---|
bin | 11100110010001001111… |
… | …11100110010100000011 |
3 | 10111112210002222120022012 |
4 | 32121010333212110003 |
5 | 112200433000011041 |
6 | 2034201302203135 |
7 | 131311225205306 |
oct | 16310477462403 |
9 | 3445702876265 |
10 | 989000000771 |
11 | 351483798742 |
12 | 13b8121234ab |
13 | 72354371663 |
14 | 35c21576b3d |
15 | 1aad5bc73eb |
hex | e644fe6503 |
989000000771 has 2 divisors, whose sum is σ = 989000000772. Its totient is φ = 989000000770.
The previous prime is 989000000683. The next prime is 989000000773. The reversal of 989000000771 is 177000000989.
989000000771 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 989000000771 - 226 = 988932891907 is a prime.
Together with 989000000773, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (989000000773) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 494500000385 + 494500000386.
It is an arithmetic number, because the mean of its divisors is an integer number (494500000386).
Almost surely, 2989000000771 is an apocalyptic number.
989000000771 is a deficient number, since it is larger than the sum of its proper divisors (1).
989000000771 is an equidigital number, since it uses as much as digits as its factorization.
989000000771 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31752, while the sum is 41.
The spelling of 989000000771 in words is "nine hundred eighty-nine billion, seven hundred seventy-one", and thus it is an aban number.
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