Base | Representation |
---|---|
bin | 11100110100010000000… |
… | …11001000100100100111 |
3 | 10111122200111212111111022 |
4 | 32122020003020210213 |
5 | 112210234000012444 |
6 | 2034505051001355 |
7 | 131351135434331 |
oct | 16321003104447 |
9 | 3448614774438 |
10 | 990125000999 |
11 | 351a00828aa2 |
12 | 13ba86a3925b |
13 | 724a3466674 |
14 | 35ccab42451 |
15 | 1ab4e84a9ee |
hex | e6880c8927 |
990125000999 has 2 divisors, whose sum is σ = 990125001000. Its totient is φ = 990125000998.
The previous prime is 990125000933. The next prime is 990125001011. The reversal of 990125000999 is 999000521099.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-990125000999 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 990125000999.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (990125000399) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 495062500499 + 495062500500.
It is an arithmetic number, because the mean of its divisors is an integer number (495062500500).
Almost surely, 2990125000999 is an apocalyptic number.
990125000999 is a deficient number, since it is larger than the sum of its proper divisors (1).
990125000999 is an equidigital number, since it uses as much as digits as its factorization.
990125000999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 590490, while the sum is 53.
The spelling of 990125000999 in words is "nine hundred ninety billion, one hundred twenty-five million, nine hundred ninety-nine", and thus it is an aban number.
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