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991000000181 is a prime number
BaseRepresentation
bin11100110101111000011…
…00111111011010110101
310111201221111100001201102
432122330030333122311
5112214032000001211
62035131545135445
7131411622005342
oct16327414773265
93451844301642
10991000000181
1135230a734914
1214008ba8a585
13725b2818669
1435d710317c9
151aba1589a3b
hexe6bc33f6b5

991000000181 has 2 divisors, whose sum is σ = 991000000182. Its totient is φ = 991000000180.

The previous prime is 991000000139. The next prime is 991000000201. The reversal of 991000000181 is 181000000199.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 973567023025 + 17432977156 = 986695^2 + 132034^2 .

It is a cyclic number.

It is not a de Polignac number, because 991000000181 - 214 = 990999983797 is a prime.

It is a super-2 number, since 2×9910000001812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (991000000681) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 495500000090 + 495500000091.

It is an arithmetic number, because the mean of its divisors is an integer number (495500000091).

Almost surely, 2991000000181 is an apocalyptic number.

It is an amenable number.

991000000181 is a deficient number, since it is larger than the sum of its proper divisors (1).

991000000181 is an equidigital number, since it uses as much as digits as its factorization.

991000000181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 29.

The spelling of 991000000181 in words is "nine hundred ninety-one billion, one hundred eighty-one", and thus it is an aban number.