Base | Representation |
---|---|
bin | 1001000001011100111011… |
… | …0111000000110110001111 |
3 | 1022010101200012001210200022 |
4 | 2100113032313000312033 |
5 | 2300014241300424401 |
6 | 33033234320052355 |
7 | 2042510322534134 |
oct | 220271667006617 |
9 | 38111605053608 |
10 | 9920550014351 |
11 | 3185310944959 |
12 | 11428041640bb |
13 | 56c671c6a5b2 |
14 | 26422b44858b |
15 | 1230c9dbb71b |
hex | 905cedc0d8f |
9920550014351 has 2 divisors, whose sum is σ = 9920550014352. Its totient is φ = 9920550014350.
The previous prime is 9920550014329. The next prime is 9920550014383. The reversal of 9920550014351 is 1534100550299.
9920550014351 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (1534100550299) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 9920550014351 - 222 = 9920545820047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (9920550814351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4960275007175 + 4960275007176.
It is an arithmetic number, because the mean of its divisors is an integer number (4960275007176).
Almost surely, 29920550014351 is an apocalyptic number.
9920550014351 is a deficient number, since it is larger than the sum of its proper divisors (1).
9920550014351 is an equidigital number, since it uses as much as digits as its factorization.
9920550014351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243000, while the sum is 44.
The spelling of 9920550014351 in words is "nine trillion, nine hundred twenty billion, five hundred fifty million, fourteen thousand, three hundred fifty-one".
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