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99212147 is a prime number
BaseRepresentation
bin1011110100111…
…01101101110011
320220200111110222
411322131231303
5200344242042
613502243255
72313201146
oct572355563
9226614428
1099212147
1151003611
122928652b
1317729018
14d26805d
158a9b2d2
hex5e9db73

99212147 has 2 divisors, whose sum is σ = 99212148. Its totient is φ = 99212146.

The previous prime is 99212123. The next prime is 99212149. The reversal of 99212147 is 74121299.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 99212147 - 26 = 99212083 is a prime.

It is a super-2 number, since 2×992121472 = 19686100224699218, which contains 22 as substring.

Together with 99212149, it forms a pair of twin primes.

It is a Chen prime.

It is equal to p5718653 and since 99212147 and 5718653 have the same sum of digits, it is a Honaker prime.

It is not a weakly prime, because it can be changed into another prime (99212149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49606073 + 49606074.

It is an arithmetic number, because the mean of its divisors is an integer number (49606074).

Almost surely, 299212147 is an apocalyptic number.

99212147 is a deficient number, since it is larger than the sum of its proper divisors (1).

99212147 is an equidigital number, since it uses as much as digits as its factorization.

99212147 is an evil number, because the sum of its binary digits is even.

The product of its digits is 9072, while the sum is 35.

The square root of 99212147 is about 9960.5294537991. The cubic root of 99212147 is about 462.9367048338.

The spelling of 99212147 in words is "ninety-nine million, two hundred twelve thousand, one hundred forty-seven".