Base | Representation |
---|---|
bin | 10110100011110000100011… |
… | …011111101101010101001101 |
3 | 111000021210112221111220221021 |
4 | 112203300203133231111031 |
5 | 101001011432023133201 |
6 | 551002234423234141 |
7 | 26616666556601665 |
oct | 2643604337552515 |
9 | 430253487456837 |
10 | 99214340052301 |
11 | 296816244a0a81 |
12 | b1644a18a8951 |
13 | 4348b4508a826 |
14 | 1a6dddd1a11a5 |
15 | b70bd53d1ea1 |
hex | 5a3c237ed54d |
99214340052301 has 4 divisors (see below), whose sum is σ = 99225120713472. Its totient is φ = 99203559391132.
The previous prime is 99214340052293. The next prime is 99214340052341. The reversal of 99214340052301 is 10325004341299.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 99214340052301 - 23 = 99214340052293 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (99214340052341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5390316781 + ... + 5390335186.
It is an arithmetic number, because the mean of its divisors is an integer number (24806280178368).
Almost surely, 299214340052301 is an apocalyptic number.
It is an amenable number.
99214340052301 is a deficient number, since it is larger than the sum of its proper divisors (10780661171).
99214340052301 is a wasteful number, since it uses less digits than its factorization.
99214340052301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10780661170.
The product of its (nonzero) digits is 233280, while the sum is 43.
The spelling of 99214340052301 in words is "ninety-nine trillion, two hundred fourteen billion, three hundred forty million, fifty-two thousand, three hundred one".
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