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9922953253 is a prime number
BaseRepresentation
bin10010011110111010…
…00100000000100101
3221121112210020212011
421033131010000211
5130310234001003
64320351154221
7500620465603
oct111735040045
927545706764
109922953253
114232280714
121b0b215971
13c21a52395
146a1c28873
153d123e46d
hex24f744025

9922953253 has 2 divisors, whose sum is σ = 9922953254. Its totient is φ = 9922953252.

The previous prime is 9922953223. The next prime is 9922953259. The reversal of 9922953253 is 3523592299.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5532830689 + 4390122564 = 74383^2 + 66258^2 .

It is a cyclic number.

It is not a de Polignac number, because 9922953253 - 25 = 9922953221 is a prime.

It is a super-2 number, since 2×99229532532 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 9922953197 and 9922953206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (9922953259) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4961476626 + 4961476627.

It is an arithmetic number, because the mean of its divisors is an integer number (4961476627).

Almost surely, 29922953253 is an apocalyptic number.

It is an amenable number.

9922953253 is a deficient number, since it is larger than the sum of its proper divisors (1).

9922953253 is an equidigital number, since it uses as much as digits as its factorization.

9922953253 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1312200, while the sum is 49.

The square root of 9922953253 is about 99614.0213674762. The cubic root of 9922953253 is about 2148.8873459011.

The spelling of 9922953253 in words is "nine billion, nine hundred twenty-two million, nine hundred fifty-three thousand, two hundred fifty-three".