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992444455501 is a prime number
BaseRepresentation
bin11100111000100100100…
…11001001101001001101
310111212200011022222220121
432130102103021221031
5112230011240034001
62035531144544541
7131462461453342
oct16342223115115
93455604288817
10992444455501
11352991027544
12140413782151
1372782b60855
143606abd67c9
151ac382b16a1
hexe7124c9a4d

992444455501 has 2 divisors, whose sum is σ = 992444455502. Its totient is φ = 992444455500.

The previous prime is 992444455451. The next prime is 992444455549. The reversal of 992444455501 is 105554444299.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 838094475625 + 154349979876 = 915475^2 + 392874^2 .

It is an emirp because it is prime and its reverse (105554444299) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 992444455501 - 211 = 992444453453 is a prime.

It is a super-2 number, since 2×9924444555012 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (992444455201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 496222227750 + 496222227751.

It is an arithmetic number, because the mean of its divisors is an integer number (496222227751).

Almost surely, 2992444455501 is an apocalyptic number.

It is an amenable number.

992444455501 is a deficient number, since it is larger than the sum of its proper divisors (1).

992444455501 is an equidigital number, since it uses as much as digits as its factorization.

992444455501 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184000, while the sum is 52.

The spelling of 992444455501 in words is "nine hundred ninety-two billion, four hundred forty-four million, four hundred fifty-five thousand, five hundred one".