9925334194103 has 4 divisors (see below), whose sum is σ = 10061297676288. Its totient is φ = 9789370711920.

The previous prime is 9925334194033. The next prime is 9925334194121. The reversal of 9925334194103 is 3014914335299.

9925334194103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 9925334194103 - 2⁸ = 9925334193847 is a prime.

It is a super-3 number, since 3×9925334194103³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (9925334191103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67981740983 + ... + 67981741128.

It is an arithmetic number, because the mean of its divisors is an integer number (2515324419072).

Almost surely, 2^{9925334194103} is an apocalyptic number.

9925334194103 is a deficient number, since it is larger than the sum of its proper divisors (135963482185).

9925334194103 is a wasteful number, since it uses less digits than its factorization.

9925334194103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 135963482184.

The product of its (nonzero) digits is 3149280, while the sum is 53.

The spelling of 9925334194103 in words is "nine trillion, nine hundred twenty-five billion, three hundred thirty-four million, one hundred ninety-four thousand, one hundred three".