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99260053067753 is a prime number
BaseRepresentation
bin10110100100011011001000…
…001101000001011111101001
3111000110011112202121201022122
4112210123020031001133221
5101002234042041132003
6551035234444001025
726623205435040344
oct2644331015013751
9430404482551278
1099260053067753
1129699a52286096
12b17131ab30175
13435024b9172b6
141a722d83d545b
15b71ead714238
hex5a46c83417e9

99260053067753 has 2 divisors, whose sum is σ = 99260053067754. Its totient is φ = 99260053067752.

The previous prime is 99260053067743. The next prime is 99260053067759. The reversal of 99260053067753 is 35776035006299.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 88661564464729 + 10598488603024 = 9416027^2 + 3255532^2 .

It is a cyclic number.

It is not a de Polignac number, because 99260053067753 - 26 = 99260053067689 is a prime.

It is a super-3 number, since 3×992600530677533 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (99260053067759) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49630026533876 + 49630026533877.

It is an arithmetic number, because the mean of its divisors is an integer number (49630026533877).

Almost surely, 299260053067753 is an apocalyptic number.

It is an amenable number.

99260053067753 is a deficient number, since it is larger than the sum of its proper divisors (1).

99260053067753 is an equidigital number, since it uses as much as digits as its factorization.

99260053067753 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64297800, while the sum is 62.

The spelling of 99260053067753 in words is "ninety-nine trillion, two hundred sixty billion, fifty-three million, sixty-seven thousand, seven hundred fifty-three".