Base | Representation |
---|---|
bin | 111011001100011… |
… | …110101000100011 |
3 | 2120012202002001112 |
4 | 323030132220203 |
5 | 4013220030242 |
6 | 242314053535 |
7 | 33416303561 |
oct | 7314365043 |
9 | 2505662045 |
10 | 993126947 |
11 | 46a659a7a |
12 | 23871a2ab |
13 | 12a9a19a7 |
14 | 95c7ca31 |
15 | 5c2c4c82 |
hex | 3b31ea23 |
993126947 has 2 divisors, whose sum is σ = 993126948. Its totient is φ = 993126946.
The previous prime is 993126923. The next prime is 993126949. The reversal of 993126947 is 749621399.
It is a strong prime.
It is an emirp because it is prime and its reverse (749621399) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 993126947 - 28 = 993126691 is a prime.
It is a super-2 number, since 2×9931269472 = 1972602265715081618, which contains 22 as substring.
Together with 993126949, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 993126895 and 993126904.
It is not a weakly prime, because it can be changed into another prime (993126949) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 496563473 + 496563474.
It is an arithmetic number, because the mean of its divisors is an integer number (496563474).
Almost surely, 2993126947 is an apocalyptic number.
993126947 is a deficient number, since it is larger than the sum of its proper divisors (1).
993126947 is an equidigital number, since it uses as much as digits as its factorization.
993126947 is an evil number, because the sum of its binary digits is even.
The product of its digits is 734832, while the sum is 50.
The square root of 993126947 is about 31513.9167194432. The cubic root of 993126947 is about 997.7037134374.
The spelling of 993126947 in words is "nine hundred ninety-three million, one hundred twenty-six thousand, nine hundred forty-seven".
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