Base | Representation |
---|---|
bin | 11100111010001111110… |
… | …00011000111101011101 |
3 | 10111221222210212121200011 |
4 | 32131013320120331131 |
5 | 112233331403110023 |
6 | 2040200300403221 |
7 | 131523655446103 |
oct | 16350770307535 |
9 | 3457883777604 |
10 | 993343410013 |
11 | 353302505359 |
12 | 140624846511 |
13 | 7289717c3b6 |
14 | 3611435dc73 |
15 | 1ac8c18350d |
hex | e747e18f5d |
993343410013 has 2 divisors, whose sum is σ = 993343410014. Its totient is φ = 993343410012.
The previous prime is 993343410001. The next prime is 993343410019. The reversal of 993343410013 is 310014343399.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 986847533604 + 6495876409 = 993402^2 + 80597^2 .
It is a cyclic number.
It is not a de Polignac number, because 993343410013 - 233 = 984753475421 is a prime.
It is a super-2 number, since 2×9933434100132 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (993343410019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 496671705006 + 496671705007.
It is an arithmetic number, because the mean of its divisors is an integer number (496671705007).
Almost surely, 2993343410013 is an apocalyptic number.
It is an amenable number.
993343410013 is a deficient number, since it is larger than the sum of its proper divisors (1).
993343410013 is an equidigital number, since it uses as much as digits as its factorization.
993343410013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 104976, while the sum is 40.
The spelling of 993343410013 in words is "nine hundred ninety-three billion, three hundred forty-three million, four hundred ten thousand, thirteen".
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