Base | Representation |
---|---|
bin | 11100111010100110111… |
… | …10101100100001010101 |
3 | 10111222111101000212022001 |
4 | 32131103132230201111 |
5 | 112234231212012411 |
6 | 2040231451235301 |
7 | 131531540444521 |
oct | 16352336544125 |
9 | 3458441025261 |
10 | 993538000981 |
11 | 3533a2333439 |
12 | 140679a48b31 |
13 | 728c8591696 |
14 | 36132134d81 |
15 | 1ac9e2bedc1 |
hex | e7537ac855 |
993538000981 has 2 divisors, whose sum is σ = 993538000982. Its totient is φ = 993538000980.
The previous prime is 993538000951. The next prime is 993538001033. The reversal of 993538000981 is 189000835399.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 914683744881 + 78854256100 = 956391^2 + 280810^2 .
It is a cyclic number.
It is not a de Polignac number, because 993538000981 - 27 = 993538000853 is a prime.
It is a super-2 number, since 2×9935380009812 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (993538000921) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 496769000490 + 496769000491.
It is an arithmetic number, because the mean of its divisors is an integer number (496769000491).
Almost surely, 2993538000981 is an apocalyptic number.
It is an amenable number.
993538000981 is a deficient number, since it is larger than the sum of its proper divisors (1).
993538000981 is an equidigital number, since it uses as much as digits as its factorization.
993538000981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2099520, while the sum is 55.
The spelling of 993538000981 in words is "nine hundred ninety-three billion, five hundred thirty-eight million, nine hundred eighty-one", and thus it is an aban number.
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •