Search a number
-
+
99380548961 is a prime number
BaseRepresentation
bin101110010001110001…
…0101101010101100001
3100111112000000222011122
41130203202231111201
53112012410031321
6113353234022025
710115512504541
oct1344342552541
9314460028148
1099380548961
11391688023a1
1217316417915
1394aa393575
144b4aa93321
1528b9b788ab
hex17238ad561

99380548961 has 2 divisors, whose sum is σ = 99380548962. Its totient is φ = 99380548960.

The previous prime is 99380548937. The next prime is 99380548963. The reversal of 99380548961 is 16984508399.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 75545820736 + 23834728225 = 274856^2 + 154385^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-99380548961 is a prime.

Together with 99380548963, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 99380548894 and 99380548903.

It is not a weakly prime, because it can be changed into another prime (99380548963) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49690274480 + 49690274481.

It is an arithmetic number, because the mean of its divisors is an integer number (49690274481).

Almost surely, 299380548961 is an apocalyptic number.

It is an amenable number.

99380548961 is a deficient number, since it is larger than the sum of its proper divisors (1).

99380548961 is an equidigital number, since it uses as much as digits as its factorization.

99380548961 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16796160, while the sum is 62.

The spelling of 99380548961 in words is "ninety-nine billion, three hundred eighty million, five hundred forty-eight thousand, nine hundred sixty-one".