Base | Representation |
---|---|
bin | 11100111011001011000… |
… | …11110110110101001011 |
3 | 10112000021111211021102222 |
4 | 32131211203312311023 |
5 | 112240341341000234 |
6 | 2040321525044255 |
7 | 131542213016132 |
oct | 16354543666513 |
9 | 3460244737388 |
10 | 993841343819 |
11 | 3535385903a5 |
12 | 14074355668b |
13 | 7294638cb9c |
14 | 36160538919 |
15 | 1acbac3e42e |
hex | e7658f6d4b |
993841343819 has 2 divisors, whose sum is σ = 993841343820. Its totient is φ = 993841343818.
The previous prime is 993841343779. The next prime is 993841343821. The reversal of 993841343819 is 918343148399.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-993841343819 is a prime.
It is a super-2 number, since 2×9938413438192 (a number of 25 digits) contains 22 as substring.
Together with 993841343821, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (993841543819) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 496920671909 + 496920671910.
It is an arithmetic number, because the mean of its divisors is an integer number (496920671910).
Almost surely, 2993841343819 is an apocalyptic number.
993841343819 is a deficient number, since it is larger than the sum of its proper divisors (1).
993841343819 is an equidigital number, since it uses as much as digits as its factorization.
993841343819 is an evil number, because the sum of its binary digits is even.
The product of its digits is 20155392, while the sum is 62.
The spelling of 993841343819 in words is "nine hundred ninety-three billion, eight hundred forty-one million, three hundred forty-three thousand, eight hundred nineteen".
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