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99418314067 is a prime number
BaseRepresentation
bin101110010010111001…
…0110001010101010011
3100111121122002122011021
41130211302301111103
53112102042022232
6113401103300311
710116451504102
oct1344562612523
9314548078137
1099418314067
1139188056926
1217326baa697
1394b5156a97
144b51ac4039
1528bd138397
hex1725cb1553

99418314067 has 2 divisors, whose sum is σ = 99418314068. Its totient is φ = 99418314066.

The previous prime is 99418314013. The next prime is 99418314119. The reversal of 99418314067 is 76041381499.

It is an a-pointer prime, because the next prime (99418314119) can be obtained adding 99418314067 to its sum of digits (52).

It is a strong prime.

It is an emirp because it is prime and its reverse (76041381499) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-99418314067 is a prime.

It is not a weakly prime, because it can be changed into another prime (99418314467) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49709157033 + 49709157034.

It is an arithmetic number, because the mean of its divisors is an integer number (49709157034).

Almost surely, 299418314067 is an apocalyptic number.

99418314067 is a deficient number, since it is larger than the sum of its proper divisors (1).

99418314067 is an equidigital number, since it uses as much as digits as its factorization.

99418314067 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1306368, while the sum is 52.

The spelling of 99418314067 in words is "ninety-nine billion, four hundred eighteen million, three hundred fourteen thousand, sixty-seven".