Base | Representation |
---|---|
bin | 11100111101010101001… |
… | …11110010000010010111 |
3 | 10112010021021001010211102 |
4 | 32132222213302002113 |
5 | 112300230000010123 |
6 | 2041032515100315 |
7 | 131613012313334 |
oct | 16365247620227 |
9 | 3463237033742 |
10 | 995000000663 |
11 | 353a82619439 |
12 | 140a075a169b |
13 | 72a9c43a356 |
14 | 3623038598b |
15 | 1ad37810028 |
hex | e7aa9f2097 |
995000000663 has 2 divisors, whose sum is σ = 995000000664. Its totient is φ = 995000000662.
The previous prime is 995000000591. The next prime is 995000000671. The reversal of 995000000663 is 366000000599.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 995000000663 - 210 = 994999999639 is a prime.
It is a super-4 number, since 4×9950000006634 (a number of 49 digits) contains 4444 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (995000000963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 497500000331 + 497500000332.
It is an arithmetic number, because the mean of its divisors is an integer number (497500000332).
Almost surely, 2995000000663 is an apocalyptic number.
995000000663 is a deficient number, since it is larger than the sum of its proper divisors (1).
995000000663 is an equidigital number, since it uses as much as digits as its factorization.
995000000663 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43740, while the sum is 38.
The spelling of 995000000663 in words is "nine hundred ninety-five billion, six hundred sixty-three", and thus it is an aban number.
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