Base | Representation |
---|---|
bin | 101110010110001111… |
… | …0111011000101000011 |
3 | 100111220110021220010122 |
4 | 1130230132323011003 |
5 | 3112314310122434 |
6 | 113420153050455 |
7 | 10122313505222 |
oct | 1345436730503 |
9 | 314813256118 |
10 | 99530551619 |
11 | 39235446634 |
12 | 173586b6a2b |
13 | 9502493735 |
14 | 4b6297ccb9 |
15 | 28c7e08c2e |
hex | 172c7bb143 |
99530551619 has 2 divisors, whose sum is σ = 99530551620. Its totient is φ = 99530551618.
The previous prime is 99530551529. The next prime is 99530551669. The reversal of 99530551619 is 91615503599.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (91615503599) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 99530551619 - 236 = 30811074883 is a prime.
It is a super-2 number, since 2×995305516192 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (99530551669) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49765275809 + 49765275810.
It is an arithmetic number, because the mean of its divisors is an integer number (49765275810).
Almost surely, 299530551619 is an apocalyptic number.
99530551619 is a deficient number, since it is larger than the sum of its proper divisors (1).
99530551619 is an equidigital number, since it uses as much as digits as its factorization.
99530551619 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1640250, while the sum is 53.
The spelling of 99530551619 in words is "ninety-nine billion, five hundred thirty million, five hundred fifty-one thousand, six hundred nineteen".
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