Search a number
-
+
99532623266513 is a prime number
BaseRepresentation
bin10110101000011000111110…
…101001110100001011010001
3111001102020002122112110120022
4112220120332221310023101
5101021220303024012023
6551404353401153225
726651665122355013
oct2650307651641321
9431366078473508
1099532623266513
1129794604029768
12b1b610a18b815
13436cb699bb388
141a815945b41b3
15b79112c3e7c8
hex5a863ea742d1

99532623266513 has 2 divisors, whose sum is σ = 99532623266514. Its totient is φ = 99532623266512.

The previous prime is 99532623266473. The next prime is 99532623266569. The reversal of 99532623266513 is 31566232623599.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 53780764930369 + 45751858336144 = 7333537^2 + 6764012^2 .

It is a cyclic number.

It is not a de Polignac number, because 99532623266513 - 228 = 99532354831057 is a prime.

It is a super-3 number, since 3×995326232665133 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (99532623266213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49766311633256 + 49766311633257.

It is an arithmetic number, because the mean of its divisors is an integer number (49766311633257).

Almost surely, 299532623266513 is an apocalyptic number.

It is an amenable number.

99532623266513 is a deficient number, since it is larger than the sum of its proper divisors (1).

99532623266513 is an equidigital number, since it uses as much as digits as its factorization.

99532623266513 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 94478400, while the sum is 62.

The spelling of 99532623266513 in words is "ninety-nine trillion, five hundred thirty-two billion, six hundred twenty-three million, two hundred sixty-six thousand, five hundred thirteen".