Base | Representation |
---|---|
bin | 11101000011101101101… |
… | …00111010111000000111 |
3 | 10112110010000122210000111 |
4 | 32201312310322320013 |
5 | 112324234023344212 |
6 | 2042400502053451 |
7 | 132063632642311 |
oct | 16416664727007 |
9 | 3473100583014 |
10 | 998425996807 |
11 | 3554804a0008 |
12 | 141602a1a287 |
13 | 731c71658c5 |
14 | 3647739c7b1 |
15 | 1ae8849eea7 |
hex | e876d3ae07 |
998425996807 has 2 divisors, whose sum is σ = 998425996808. Its totient is φ = 998425996806.
The previous prime is 998425996759. The next prime is 998425996811. The reversal of 998425996807 is 708699524899.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 998425996807 - 211 = 998425994759 is a prime.
It is a super-2 number, since 2×9984259968072 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (998425996207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 499212998403 + 499212998404.
It is an arithmetic number, because the mean of its divisors is an integer number (499212998404).
Almost surely, 2998425996807 is an apocalyptic number.
998425996807 is a deficient number, since it is larger than the sum of its proper divisors (1).
998425996807 is an equidigital number, since it uses as much as digits as its factorization.
998425996807 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 705438720, while the sum is 76.
The spelling of 998425996807 in words is "nine hundred ninety-eight billion, four hundred twenty-five million, nine hundred ninety-six thousand, eight hundred seven".
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