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999013439 is a prime number
BaseRepresentation
bin111011100010111…
…011110000111111
32120121211010210202
4323202323300333
54021221412224
6243044154115
733520321424
oct7342736077
92517733722
10999013439
11472a0a646
1223a69893b
1312bc83118
1496971d4b
155ca88eae
hex3b8bbc3f

999013439 has 2 divisors, whose sum is σ = 999013440. Its totient is φ = 999013438.

The previous prime is 999013403. The next prime is 999013459. The reversal of 999013439 is 934310999.

It is a strong prime.

It is an emirp because it is prime and its reverse (934310999) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-999013439 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 999013393 and 999013402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (999013459) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 499506719 + 499506720.

It is an arithmetic number, because the mean of its divisors is an integer number (499506720).

Almost surely, 2999013439 is an apocalyptic number.

999013439 is a deficient number, since it is larger than the sum of its proper divisors (1).

999013439 is an equidigital number, since it uses as much as digits as its factorization.

999013439 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 236196, while the sum is 47.

The square root of 999013439 is about 31607.1738534150. The cubic root of 999013439 is about 999.6710381293.

The spelling of 999013439 in words is "nine hundred ninety-nine million, thirteen thousand, four hundred thirty-nine".