Base | Representation |
---|---|
bin | 1001000101100001001001… |
… | …0111010110010010100111 |
3 | 1022101001222021222102021101 |
4 | 2101120102113112102213 |
5 | 2302140320410302444 |
6 | 33125305523300531 |
7 | 2050532322134452 |
oct | 221302227262247 |
9 | 38331867872241 |
10 | 9990402040999 |
11 | 32019a65593a6 |
12 | 115425951a747 |
13 | 576124845643 |
14 | 267776542499 |
15 | 124d174ed3d4 |
hex | 916125d64a7 |
9990402040999 has 2 divisors, whose sum is σ = 9990402041000. Its totient is φ = 9990402040998.
The previous prime is 9990402040951. The next prime is 9990402041021.
9990402040999 is nontrivially palindromic in base 10.
It is a strong prime.
It is a palprime.
It is a cyclic number.
It is not a de Polignac number, because 9990402040999 - 215 = 9990402008231 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 9990402040999.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (9990402040939) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4995201020499 + 4995201020500.
It is an arithmetic number, because the mean of its divisors is an integer number (4995201020500).
Almost surely, 29990402040999 is an apocalyptic number.
9990402040999 is a deficient number, since it is larger than the sum of its proper divisors (1).
9990402040999 is an equidigital number, since it uses as much as digits as its factorization.
9990402040999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17006112, while the sum is 64.
The spelling of 9990402040999 in words is "nine trillion, nine hundred ninety billion, four hundred two million, forty thousand, nine hundred ninety-nine".
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