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999130461401 is a prime number
BaseRepresentation
bin11101000101000001101…
…00001111010011011001
310112111221010020021202202
432202200310033103121
5112332204344231101
62042554425135545
7132120245540042
oct16424064172331
93474833207682
10999130461401
11355802109756
1214177a92a5b5
13732aa0a9167
1436502b798c9
151aeca25536b
hexe8a0d0f4d9

999130461401 has 2 divisors, whose sum is σ = 999130461402. Its totient is φ = 999130461400.

The previous prime is 999130461361. The next prime is 999130461403. The reversal of 999130461401 is 104164031999.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 999040230400 + 90231001 = 999520^2 + 9499^2 .

It is a cyclic number.

It is not a de Polignac number, because 999130461401 - 26 = 999130461337 is a prime.

Together with 999130461403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (999130461403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 499565230700 + 499565230701.

It is an arithmetic number, because the mean of its divisors is an integer number (499565230701).

Almost surely, 2999130461401 is an apocalyptic number.

It is an amenable number.

999130461401 is a deficient number, since it is larger than the sum of its proper divisors (1).

999130461401 is an equidigital number, since it uses as much as digits as its factorization.

999130461401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 209952, while the sum is 47.

The spelling of 999130461401 in words is "nine hundred ninety-nine billion, one hundred thirty million, four hundred sixty-one thousand, four hundred one".