Base | Representation |
---|---|
bin | 1001000101101011011000… |
… | …1011111100001101010111 |
3 | 1022101100001211201022102222 |
4 | 2101122312023330031113 |
5 | 2302211433012422012 |
6 | 33130442344452555 |
7 | 2050660404565343 |
oct | 221326613741527 |
9 | 38340054638388 |
10 | 9993150514007 |
11 | 3203086a428a1 |
12 | 11548a5a7a15b |
13 | 5764720a142b |
14 | 267957592623 |
15 | 124e2895a972 |
hex | 916b62fc357 |
9993150514007 has 2 divisors, whose sum is σ = 9993150514008. Its totient is φ = 9993150514006.
The previous prime is 9993150513967. The next prime is 9993150514021. The reversal of 9993150514007 is 7004150513999.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 9993150514007 - 214 = 9993150497623 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 9993150514007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (9993150514307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4996575257003 + 4996575257004.
It is an arithmetic number, because the mean of its divisors is an integer number (4996575257004).
Almost surely, 29993150514007 is an apocalyptic number.
9993150514007 is a deficient number, since it is larger than the sum of its proper divisors (1).
9993150514007 is an equidigital number, since it uses as much as digits as its factorization.
9993150514007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1530900, while the sum is 53.
The spelling of 9993150514007 in words is "nine trillion, nine hundred ninety-three billion, one hundred fifty million, five hundred fourteen thousand, seven".
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