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999936964003 is a prime number
BaseRepresentation
bin11101000110100001110…
…00110011010110100011
310112121000022210212100111
432203100320303112203
5112340332330322003
62043210435232151
7132146240645425
oct16432070632643
93477008725314
10999936964003
1135608639102a
12141964a48657
13733a81c7a33
143657bd18815
151b025e63e6d
hexe8d0e335a3

999936964003 has 2 divisors, whose sum is σ = 999936964004. Its totient is φ = 999936964002.

The previous prime is 999936964001. The next prime is 999936964057. The reversal of 999936964003 is 300469639999.

999936964003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 999936964003 - 21 = 999936964001 is a prime.

Together with 999936964001, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 999936964003.

It is not a weakly prime, because it can be changed into another prime (999936964001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 499968482001 + 499968482002.

It is an arithmetic number, because the mean of its divisors is an integer number (499968482002).

Almost surely, 2999936964003 is an apocalyptic number.

999936964003 is a deficient number, since it is larger than the sum of its proper divisors (1).

999936964003 is an equidigital number, since it uses as much as digits as its factorization.

999936964003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 76527504, while the sum is 67.

The spelling of 999936964003 in words is "nine hundred ninety-nine billion, nine hundred thirty-six million, nine hundred sixty-four thousand, three".