Base | Representation |
---|---|
bin | 11101000110100100111… |
… | …00000111110111111101 |
3 | 10112121002010210122110102 |
4 | 32203102130013313331 |
5 | 112340411012002232 |
6 | 2043213205250445 |
7 | 132150005155151 |
oct | 16432234076775 |
9 | 3477063718412 |
10 | 999963000317 |
11 | 35609a054546 |
12 | 141971703a25 |
13 | 733b0712838 |
14 | 36581575061 |
15 | 1b0283a8662 |
hex | e8d2707dfd |
999963000317 has 2 divisors, whose sum is σ = 999963000318. Its totient is φ = 999963000316.
The previous prime is 999963000251. The next prime is 999963000353. The reversal of 999963000317 is 713000369999.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 934526290681 + 65436709636 = 966709^2 + 255806^2 .
It is an emirp because it is prime and its reverse (713000369999) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 999963000317 - 222 = 999958806013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (999963000397) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 499981500158 + 499981500159.
It is an arithmetic number, because the mean of its divisors is an integer number (499981500159).
Almost surely, 2999963000317 is an apocalyptic number.
It is an amenable number.
999963000317 is a deficient number, since it is larger than the sum of its proper divisors (1).
999963000317 is an equidigital number, since it uses as much as digits as its factorization.
999963000317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2480058, while the sum is 56.
The spelling of 999963000317 in words is "nine hundred ninety-nine billion, nine hundred sixty-three million, three hundred seventeen", and thus it is an aban number.
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