9999642433471 has 2 divisors, whose sum is σ = 9999642433472. Its totient is φ = 9999642433470.

The previous prime is 9999642433453. The next prime is 9999642433493. The reversal of 9999642433471 is 1743342469999.

9999642433471 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 9999642433471 - 2¹¹ = 9999642431423 is a prime.

It is a super-3 number, since 3×9999642433471³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 9999642433471.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (9999642433771) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4999821216735 + 4999821216736.

It is an arithmetic number, because the mean of its divisors is an integer number (4999821216736).

Almost surely, 2^{9999642433471} is an apocalyptic number.

9999642433471 is a deficient number, since it is larger than the sum of its proper divisors (1).

9999642433471 is an equidigital number, since it uses as much as digits as its factorization.

9999642433471 is an evil number, because the sum of its binary digits is even.

The product of its digits is 317447424, while the sum is 70.

The spelling of 9999642433471 in words is "nine trillion, nine hundred ninety-nine billion, six hundred forty-two million, four hundred thirty-three thousand, four hundred seventy-one".