Base | Representation |
---|---|
bin | 11101000110100111000… |
… | …00110010010110100111 |
3 | 10112121010101200010112011 |
4 | 32203103200302112213 |
5 | 112340430114000403 |
6 | 2043215051135051 |
7 | 132150314153521 |
oct | 16432340622647 |
9 | 3477111603464 |
10 | 999981000103 |
11 | 3560a9228aa8 |
12 | 141977744487 |
13 | 733b43756b7 |
14 | 36583adca11 |
15 | 1b029c61a6d |
hex | e8d38325a7 |
999981000103 has 2 divisors, whose sum is σ = 999981000104. Its totient is φ = 999981000102.
The previous prime is 999981000059. The next prime is 999981000121. The reversal of 999981000103 is 301000189999.
999981000103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 999981000103 - 217 = 999980869031 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (999981000803) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 499990500051 + 499990500052.
It is an arithmetic number, because the mean of its divisors is an integer number (499990500052).
Almost surely, 2999981000103 is an apocalyptic number.
999981000103 is a deficient number, since it is larger than the sum of its proper divisors (1).
999981000103 is an equidigital number, since it uses as much as digits as its factorization.
999981000103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 157464, while the sum is 49.
The spelling of 999981000103 in words is "nine hundred ninety-nine billion, nine hundred eighty-one million, one hundred three", and thus it is an aban number.
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