999984000133 has 2 divisors, whose sum is σ = 999984000134. Its totient is φ = 999984000132.

The previous prime is 999984000031. The next prime is 999984000139. The reversal of 999984000133 is 331000489999.

999984000133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 795551611969 + 204432388164 = 891937^2 + 452142^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-999984000133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (999984000139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 499992000066 + 499992000067.

It is an arithmetic number, because the mean of its divisors is an integer number (499992000067).

Almost surely, 2^999984000133 is an apocalyptic number.

It is an amenable number.

999984000133 is a deficient number, since it is larger than the sum of its proper divisors (1).

999984000133 is an equidigital number, since it uses as much as digits as its factorization.

999984000133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1889568, while the sum is 55.

The spelling of 999984000133 in words is "nine hundred ninety-nine billion, nine hundred eighty-four million, one hundred thirty-three", and thus it is an aban number.