Base | Representation |
---|---|
bin | 1110001101011111101001101… |
… | …1111101011110010100011011 |
3 | 11212010201001102001212202110112 |
4 | 3203113322123331132110123 |
5 | 2022032444144120024011 |
6 | 13502453331241434535 |
7 | 420430414362164564 |
oct | 34327723375362433 |
9 | 4763631361782415 |
10 | 999999852111131 |
11 | 26a6a3612635533 |
12 | 941a680719ba4b |
13 | 33bca773517671 |
14 | 138d2372dbb16b |
15 | 7a9245733758b |
hex | 38d7e9bf5e51b |
999999852111131 has 2 divisors, whose sum is σ = 999999852111132. Its totient is φ = 999999852111130.
The previous prime is 999999852111107. The next prime is 999999852111133. The reversal of 999999852111131 is 131111258999999.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 999999852111131 - 26 = 999999852111067 is a prime.
It is a super-2 number, since 2×9999998521111312 (a number of 31 digits) contains 22 as substring.
Together with 999999852111133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (999999852111133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 499999926055565 + 499999926055566.
It is an arithmetic number, because the mean of its divisors is an integer number (499999926055566).
Almost surely, 2999999852111131 is an apocalyptic number.
999999852111131 is a deficient number, since it is larger than the sum of its proper divisors (1).
999999852111131 is an equidigital number, since it uses as much as digits as its factorization.
999999852111131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 127545840, while the sum is 77.
The spelling of 999999852111131 in words is "nine hundred ninety-nine trillion, nine hundred ninety-nine billion, eight hundred fifty-two million, one hundred eleven thousand, one hundred thirty-one".
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