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999999950062513 is a prime number
BaseRepresentation
bin1110001101011111101010000…
…1110011001000001110110001
311212010201001122220012012111111
43203113322201303020032301
52022032444344204000023
613502453345101113321
7420430416661565251
oct34327724163101661
94763631586165444
10999999950062513
1126a6a3662957894
12941a6833b58841
1333bca78a8c186a
14138d2381dd7961
157a92460c3500d
hex38d7ea1cc83b1

999999950062513 has 2 divisors, whose sum is σ = 999999950062514. Its totient is φ = 999999950062512.

The previous prime is 999999950062511. The next prime is 999999950062517. The reversal of 999999950062513 is 315260059999999.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 750116950157169 + 249882999905344 = 27388263^2 + 15807688^2 .

It is a cyclic number.

It is not a de Polignac number, because 999999950062513 - 21 = 999999950062511 is a prime.

Together with 999999950062511, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (999999950062511) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 499999975031256 + 499999975031257.

It is an arithmetic number, because the mean of its divisors is an integer number (499999975031257).

Almost surely, 2999999950062513 is an apocalyptic number.

It is an amenable number.

999999950062513 is a deficient number, since it is larger than the sum of its proper divisors (1).

999999950062513 is an equidigital number, since it uses as much as digits as its factorization.

999999950062513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4304672100, while the sum is 85.

The spelling of 999999950062513 in words is "nine hundred ninety-nine trillion, nine hundred ninety-nine billion, nine hundred fifty million, sixty-two thousand, five hundred thirteen".