999999999999043 has 2 divisors, whose sum is σ = 999999999999044. Its totient is φ = 999999999999042.

The previous prime is 999999999998939. The next prime is 999999999999071. The reversal of 999999999999043 is 340999999999999.

It is a strong prime.

It is an emirp because it is prime and its reverse (340999999999999) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 999999999999043 - 2¹³ = 999999999990851 is a prime.

It is a super-9 number, since 9×999999999999043⁹ (a number of 136 digits) contains 999999999 as substring.

It is not a weakly prime, because it can be changed into another prime (999999999999643) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 499999999999521 + 499999999999522.

It is an arithmetic number, because the mean of its divisors is an integer number (499999999999522).

Almost surely, 2^{999999999999043} is an apocalyptic number.

999999999999043 is a deficient number, since it is larger than the sum of its proper divisors (1).

999999999999043 is an equidigital number, since it uses as much as digits as its factorization.

999999999999043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3389154437772, while the sum is 115.

The spelling of 999999999999043 in words is "nine hundred ninety-nine trillion, nine hundred ninety-nine billion, nine hundred ninety-nine million, nine hundred ninety-nine thousand, forty-three".