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BaseRepresentation
bin1110011
311021
41303
5430
6311
7223
oct163
9137
10115
11a5
1297
138b
1483
157a
hex73

115 has 4 divisors (see below), whose sum is σ = 144. Its totient is φ = 88.

The previous prime is 113. The next prime is 127. The reversal of 115 is 511.

Adding to 115 its reverse (511), we get a palindrome (626).

It can be divided in two parts, 11 and 5, that multiplied together give a palindrome (55).

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 511 = 773.

It is a cyclic number.

It is not a de Polignac number, because 115 - 21 = 113 is a prime.

It is a nude number because it is divisible by every one of its digits and also a Zuckerman number because it is divisible by the product of its digits.

It is a Duffinian number.

115 is a lucky number.

It is a plaindrome in base 7, base 9, base 10, base 13 and base 15.

It is a nialpdrome in base 5, base 6, base 11, base 12, base 14 and base 16.

It is a zygodrome in base 2.

It is a junction number, because it is equal to n+sod(n) for n = 98 and 107.

It is a pernicious number, because its binary representation contains a prime number (5) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7 + ... + 16.

It is an arithmetic number, because the mean of its divisors is an integer number (36).

115 is a deficient number, since it is larger than the sum of its proper divisors (29).

115 is an equidigital number, since it uses as much as digits as its factorization.

115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28.

The product of its digits is 5, while the sum is 7.

The square root of 115 is about 10.7238052948. The cubic root of 115 is about 4.8629441311.

The spelling of 115 in words is "one hundred fifteen", and thus it is an aban number.

Divisors: 1 5 23 115