100000010000003 has 2 divisors, whose sum is σ = 100000010000004. Its totient is φ = 100000010000002.

The previous prime is 100000009999999. The next prime is 100000010000057. The reversal of 100000010000003 is 300000010000001.

It is a weak prime.

It is an emirp because it is prime and its reverse (300000010000001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100000010000003 - 2² = 100000009999999 is a prime.

It is not a weakly prime, because it can be changed into another prime (100000010000063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50000005000001 + 50000005000002.

It is an arithmetic number, because the mean of its divisors is an integer number (50000005000002).

Almost surely, 2^{100000010000003} is an apocalyptic number.

100000010000003 is a deficient number, since it is larger than the sum of its proper divisors (1).

100000010000003 is an equidigital number, since it uses as much as digits as its factorization.

100000010000003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 5.

Adding to 100000010000003 its reverse (300000010000001), we get a palindrome (400000020000004).

The spelling of 100000010000003 in words is "one hundred trillion, ten million, three", and thus it is an aban number.