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10000001100113 is a prime number
BaseRepresentation
bin1001000110000100111010…
…0000110110100101010001
31022101222202021022010220022
42101201032200312211101
52302320000240200423
633133534224353225
72051322230605523
oct221411640664521
938358667263808
1010000001100113
113205a81a15602
121156098175815
13576cc445218b
14268007337a13
151251ca0addc8
hex9184e836951

10000001100113 has 2 divisors, whose sum is σ = 10000001100114. Its totient is φ = 10000001100112.

The previous prime is 10000001100109. The next prime is 10000001100139. The reversal of 10000001100113 is 31100110000001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6392235154369 + 3607765945744 = 2528287^2 + 1899412^2 .

It is a cyclic number.

It is not a de Polignac number, because 10000001100113 - 22 = 10000001100109 is a prime.

It is a super-2 number, since 2×100000011001132 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 10000001100113.

It is not a weakly prime, because it can be changed into another prime (10000001100143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000000550056 + 5000000550057.

It is an arithmetic number, because the mean of its divisors is an integer number (5000000550057).

Almost surely, 210000001100113 is an apocalyptic number.

It is an amenable number.

10000001100113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10000001100113 is an equidigital number, since it uses as much as digits as its factorization.

10000001100113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 8.

Adding to 10000001100113 its reverse (31100110000001), we get a palindrome (41100111100114).

The spelling of 10000001100113 in words is "ten trillion, one million, one hundred thousand, one hundred thirteen".