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10000010000081 is a prime number
BaseRepresentation
bin1001000110000100111100…
…0010110011011011010001
31022101222202220001022100202
42101201033002303123101
52302320010030000311
633133535143224545
72051322366344123
oct221411702633321
938358686038322
1010000010000081
113205a86a44252
12115609b148155
13576cc624a12a
142680085b3213
151251cac6ae3b
hex9184f0b36d1

10000010000081 has 2 divisors, whose sum is σ = 10000010000082. Its totient is φ = 10000010000080.

The previous prime is 10000010000077. The next prime is 10000010000111. The reversal of 10000010000081 is 18000001000001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9997074094225 + 2935905856 = 3161815^2 + 54184^2 .

It is an emirp because it is prime and its reverse (18000001000001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10000010000081 - 22 = 10000010000077 is a prime.

It is a super-2 number, since 2×100000100000812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10000010000381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000005000040 + 5000005000041.

It is an arithmetic number, because the mean of its divisors is an integer number (5000005000041).

Almost surely, 210000010000081 is an apocalyptic number.

It is an amenable number.

10000010000081 is a deficient number, since it is larger than the sum of its proper divisors (1).

10000010000081 is an equidigital number, since it uses as much as digits as its factorization.

10000010000081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 11.

Adding to 10000010000081 its reverse (18000001000001), we get a palindrome (28000011000082).

The spelling of 10000010000081 in words is "ten trillion, ten million, eighty-one", and thus it is an aban number and an uban number.