100000110131 has 2 divisors, whose sum is σ = 100000110132. Its totient is φ = 100000110130.

The previous prime is 100000110113. The next prime is 100000110173. The reversal of 100000110131 is 131011000001.

Together with previous prime (100000110113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 100000110131 - 2¹⁰ = 100000109107 is a prime.

It is a super-2 number, since 2×100000110131² (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (100000110181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50000055065 + 50000055066.

It is an arithmetic number, because the mean of its divisors is an integer number (50000055066).

Almost surely, 2^100000110131 is an apocalyptic number.

100000110131 is a deficient number, since it is larger than the sum of its proper divisors (1).

100000110131 is an equidigital number, since it uses as much as digits as its factorization.

100000110131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 8.

Adding to 100000110131 its reverse (131011000001), we get a palindrome (231011110132).

The spelling of 100000110131 in words is "one hundred billion, one hundred ten thousand, one hundred thirty-one".