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10000044130019 is a prime number
BaseRepresentation
bin1001000110000101000100…
…0100111111111011100011
31022101222212021021021211112
42101201101010333323203
52302320042244130034
633133542402533535
72051323262423246
oct221412104777343
938358767237745
1010000044130019
113205aa4235609
1211560aa6672ab
13577000339b68
1426800cd3925d
151251cdc5d7ce
hex9185113fee3

10000044130019 has 2 divisors, whose sum is σ = 10000044130020. Its totient is φ = 10000044130018.

The previous prime is 10000044129989. The next prime is 10000044130099. The reversal of 10000044130019 is 91003144000001.

10000044130019 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10000044130019 - 228 = 9999775694563 is a prime.

It is a super-2 number, since 2×100000441300192 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10000044129976 and 10000044130003.

It is not a weakly prime, because it can be changed into another prime (10000044130099) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000022065009 + 5000022065010.

It is an arithmetic number, because the mean of its divisors is an integer number (5000022065010).

Almost surely, 210000044130019 is an apocalyptic number.

10000044130019 is a deficient number, since it is larger than the sum of its proper divisors (1).

10000044130019 is an equidigital number, since it uses as much as digits as its factorization.

10000044130019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 23.

The spelling of 10000044130019 in words is "ten trillion, forty-four million, one hundred thirty thousand, nineteen".