Base | Representation |
---|---|
bin | 1001000110000101010110… |
… | …1110011011100101010011 |
3 | 1022102000001200222120121111 |
4 | 2101201111232123211103 |
5 | 2302320222224200201 |
6 | 33133554230034151 |
7 | 2051325230233156 |
oct | 221412556334523 |
9 | 38360050876544 |
10 | 10000122100051 |
11 | 320603424a656 |
12 | 11561107a8957 |
13 | 577013539285 |
14 | 268019433c9d |
15 | 1251d5a10b51 |
hex | 91855b9b953 |
10000122100051 has 2 divisors, whose sum is σ = 10000122100052. Its totient is φ = 10000122100050.
The previous prime is 10000122100043. The next prime is 10000122100121. The reversal of 10000122100051 is 15000122100001.
10000122100051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10000122100051 - 23 = 10000122100043 is a prime.
It is not a weakly prime, because it can be changed into another prime (10000122100351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000061050025 + 5000061050026.
It is an arithmetic number, because the mean of its divisors is an integer number (5000061050026).
Almost surely, 210000122100051 is an apocalyptic number.
10000122100051 is a deficient number, since it is larger than the sum of its proper divisors (1).
10000122100051 is an equidigital number, since it uses as much as digits as its factorization.
10000122100051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20, while the sum is 13.
Adding to 10000122100051 its reverse (15000122100001), we get a palindrome (25000244200052).
The spelling of 10000122100051 in words is "ten trillion, one hundred twenty-two million, one hundred thousand, fifty-one".
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