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100010031311 = 174315737481
BaseRepresentation
bin101110100100100001…
…1111111100011001111
3100120010212111222121202
41131021003333203033
53114310032000221
6113535522020115
710140225145211
oct1351103774317
9316125458552
10100010031311
1139461067843
12174711a763b
13957a912628
144baa5125b1
15290506bd0b
hex17490ff8cf

100010031311 has 4 divisors (see below), whose sum is σ = 100015786224. Its totient is φ = 100004276400.

The previous prime is 100010031299. The next prime is 100010031349. The reversal of 100010031311 is 113130010001.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100010031311 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100010031292 and 100010031301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100010031811) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2851310 + ... + 2886171.

It is an arithmetic number, because the mean of its divisors is an integer number (25003946556).

Almost surely, 2100010031311 is an apocalyptic number.

100010031311 is a deficient number, since it is larger than the sum of its proper divisors (5754913).

100010031311 is an equidigital number, since it uses as much as digits as its factorization.

100010031311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5754912.

The product of its (nonzero) digits is 9, while the sum is 11.

Adding to 100010031311 its reverse (113130010001), we get a palindrome (213140041312).

The spelling of 100010031311 in words is "one hundred billion, ten million, thirty-one thousand, three hundred eleven".

Divisors: 1 17431 5737481 100010031311